presario2100 Posted April 16, 2008 Report Posted April 16, 2008 i hv a mathematic question, hope someone can show me a formula to calculate this. example: electro-pneumatic valve if input 4mA = 10% (valve open) 20mA = 100% when 10mA = ?
Mickey Posted April 16, 2008 Report Posted April 16, 2008 (10ma-4ma) / (20ma-2ma) * (100%-10%) + 10 = Percent Valve Open Or ( Raw ma Value-ma Min) / (ma Range) * (Percent range) + Offset = Percent Valve Open
presario2100 Posted April 16, 2008 Author Report Posted April 16, 2008 Minimum input is 4mA, Maximum input is 20mA Valve Minimum open is 10%, Maximum open is 100%
presario2100 Posted April 16, 2008 Author Report Posted April 16, 2008 Thanks Mickey. I got ur answer, thank you so much.
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