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Posted

A motor will be controlled by two switches.The Go switch will start the motor and the Stop switch will stop it. If the Stop switch was used to stop the motor, the Go switch must be thrown twice to start the motor. When the motor is active a light should be turned on. The Stop switch will be wired as normally closed.


Posted

Ah well, fair do's you have had a go.

It's a strange task to be set seing as the stop button is the only way to stop the motor (and you said 'if)

and then having to press start twice to make it go again but if that is what it is.............

Here's some of YOUR code slightly alteredlogic.png.1a29fb7bc6e509eb3e22adb3a9a14a

There are some differences

1, why have I made the stop button N/O

2, why is MO now in series with the start button

3, What happens to the coil of MO when the stop is pressed

 

Posted

Thanks.

Yes the question needs some review as it seems not to be workable as it is.It is a college question as I tutor college kids when I'm free.I wanted to find a better way to tackle the question.

Regards.

 

Posted

Just a hint:

Create a counter with a preset of '2' and increment the count with the start button.

Q1. How will you control when the output turns on?

Q2. What is the simplest way for the stop button to re-initialise everything.

Q3. Can you guarantee that STOP will override START?

Two lines of ladder should do the trick.

Note: it is best practice to wire the STOP button using a normally closed contact arrangement. That way, if a wire falls off or gets cut the circuit will stop.

Posted

Why have you done it?

To look clever¿

 

Most could do the simple task but the poster learns nothing.

 

I was doing in parts and asking why....... Sigh

 

 

 

 

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