Siscodjo Posted May 14 Report Posted May 14 (edited) Found from old PLC SHARP which the function of the circuit attached is 4 bits (M21 to M24) down counting by pulse from SM412 (1 sec clock) and this pulse can be replaced by push button. This could be useful if somebody knows how make it able to count up. Any help is appreciated. I presented using Mitsubishi Q Series. GXWorks2 BINARY COUNTER.gxw Edited May 14 by Siscodjo Add some notes
SergeyBorchshev Posted May 14 Report Posted May 14 Not sure what is your counting is for, but in Mitsubishi PLC you have DECO function. DECO[D1 M21 K2] put it in the very beginning of your ladder. You can set D1 to 1 to turn M21 on, 2 to turn M22 on, 4 to turn M23 on and 8 to turn M24 on. D1 is your control word, and DECO will decode it to binary starting from M21 for K2 (four bits, 2^k2) starting with lower bit (lower bit goes to M21). So instead of counting up or down, in your step ladder you changing value of D1 as you need (you can turn your coils individually or any other pattern changing D1 from 0 to 15) Hope this helps. Sergey
WattUp Posted May 14 Report Posted May 14 We also use DECO for our step sequence logic. But the result is not binary, its N-th bit on. so D1 = 3, M23 would be on, not M21 & M22 If you just want to count in binary, SM412 INCP D0 SM400 BIN D0 D10
SergeyBorchshev Posted May 15 Report Posted May 15 22 hours ago, WattUp said: We also use DECO for our step sequence logic. But the result is not binary, its N-th bit on. so D1 = 3, M23 would be on, not M21 & M22 If you just want to count in binary, SM412 INCP D0 SM400 BIN D0 D10 You are correct, with K2 it converts only two low bits from D1. So D1 is in the range of 0 to 3 rest of it would be ignored. And yes only one coil in a time will be on. I missed the point of binary counting from OP program. Seems like whole intension was to build a step logic, so I thought DECO will do it just easier then all that. 1
Dave W. Posted May 21 Report Posted May 21 I don't fully understand what the OP wants with the program, nor do I really understand ladder. Especially in the lower networks, something must be wrong, or is it necessarily this way? In ST language, I would do it this way. INCP(M0, D0); (* Up *) DECP(M1, D0); (* Down *) LIMIT(TRUE, 0, 15, D0, D0 ); K1M21 := D0; (* Write binary to M21..M24 *) The command K1M21 writes 1 nibble (4 bits) from M21 as binary value of D0. 1
Solution Siscodjo Posted May 30 Author Solution Report Posted May 30 Hi All, Sorry for the very late response, just came back from remote job. Thanks to the solutions given. I did the Sergey's advice.
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