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Posted (edited)
I have never used one of these, but this was about all I could dig up. Is it as simple as a voltage transducer? Hope this helps. http://www.a-a-c.com/N3%20WS%205%20ACCD%20ACVT/108X-D.pdf http://www.a-a-c.com/6acvoltagexducr/6%20A...age%20Xducr.htm Edited by robh
Posted
Thanks, also found one by Phoenix Contact. Part Number MCR-VAC-UI-0-DC/2811103. Anyone ever used one of these or any type these. Know some can be fragile. Guess I should mention this is going on a resistance welder
Posted
I would think a cheap and dirty way to do it would be to use a signal isolator. Lots of drive makers use them to condition signals of various voltages coming in, and prep it for a 0-10VDC or 4-20mA out put, usually user configurable. Check with Extron or Minarik for a very user friendly condtioner. Hope this helps, Beuwolf
Posted
The cheapest possible solution I can find is this one (that doesn't necessarily mean it's the best): NB: This will only work if you can use -10 V to 10 V instead of 0-10 V. 1) Use a voltage divider to scale down the voltage to reasonable values (slightly below 1:2 seems reasonable - 15*sqrt(2) is just about 20 V, just use neighbor values in a resistance series or something). 2) Connect the output from the voltage divider to your analog input. 3) Do fancy signal analysis in the PLC software to calculate the mean absolute difference to 0 V over a couple of whole AC periods (100 ms, 200 ms, 300 ms etc = smart choice, multiple of 1/60 as well as of 1/50, so it works for us in Europe as well).
Posted (edited)
Or use 4 diodes in a bridge rectifier formation, a capacitor of about 1000micro farad 40v+ rated and 2 500ohm resistors The bridge rectifier would make the voltage positive, the capacitor will remove the ripple and the 2 resistors are the potential divider to take the volts from 20 to 10. Total cost of parts = peanuts. Output = 0-10v. Can be found at any hobby shop or electronics parts supplier. No fancy software required, sorry TERdON Probably all thats in the units that robh suggested. Edited by benbrad
Posted
Yeah, I said my solution probably wasn't the smartest. I considered your solution as well, but decided on mine instead. 1) I like programming. :) 2) We didn't learn what amount of current we can draw from the AC circuit - if low (ok, that's not very probable), the usual solution just won't work, you'll have to add an opamp as well (ok, that's peanuts as well, but connecting the parts should be counted as well IMHO). So yeah, unless the possible current draw is very low, your solution would probably be smarter as the cost is minimal compared to the PLC anyway. And if the current is limited, just add the above mentioned op amp (a 24V/-24V one would be suitable) before your circuit and we can disregard that as well. My solution might just be more suited in a microcontroller implementation though, where the cost of the controller easily goes below SEK 10 / €1 / $1 / £1... :)
Posted
I do something similiar to Terdon's setup on Controllogix. But this one will have a Micrologix and I am worried that I will not be able to capture the sin wave and calculate the AC voltage. Response time must be fairly low. benbrad - You solution will work but I am looking for something more like robh suggested so maintenance can easily replace it if it goes bad. Thanks for all the suggestions
Posted
chap and dirty DIY solutions will not produce good results because diodes used for rectifying will distort signal and input signal lower than some +/- 0.7V will be ignored. besides 1000uF filter capacitor with 500R resistors(s) would be way to slow for changing signals. if one still wants to do it himself, than rectifying should be done with better circuit. here is one using OpAmp. after rectification, one still has to filter and scale signal but this is very simple.

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